Problem Statment
Given an unsorted integer array, find the first missing
                          positive integer.
                          Example 1:
                          [1,2,0]
                        >> 3
                      
Given an unsorted integer array, find the first missing
                          positive integer.
                          Example 1:
                          [1,2,0]
                        >> 3
                      
                            Sort the vector array and take a key variable as 1.
                            If the array element is greater than key then the
                            first missing positive integer is key and if the the
                            array element is equal to key then increment the key
                             by 1 and find the first missing positive integer.
Time and Space Complexity : 
Time - O(n)
Space - O(n)
Pseudocode  :
	sort(a)
	for(i=0 to n)
		   if(a[i]>0)
			    if(a[i]>key)
				     key
			    else if(a[i]==key)
				     key++
  
                          
void missing_integer(vector<int>a)
{
	int key=1,k;
	sort(a.begin(),a.end());
	for(int i=0;i<a.size();i++)
	{
		if(a[i]>0)
		{
			if(a[i]>key)
			  k=key;
			else if(a[i]==key)
				k=key++;
		}
	}
	cout<<k;
}